121=25x^2

Solution for 121=25x^2 equation:

121=25x^2

We move all terms to the left:

121-(25x^2)=0

a = -25; b = 0; c = +121;
Δ = b2-4ac
Δ = 02-4·(-25)·121
Δ = 12100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12100}=110$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-110}{2*-25}=\frac{-110}{-50}
=2+1/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+110}{2*-25}=\frac{110}{-50}
=-2+1/5
$